Question

a2 -2ab +b2 - c2 factorise it

Answer 1

$a { }^{2} - 2ab + b {}^{2} - c {}^{2}$
$(a - b) {}^{2} - c {}^{2}$
$(a - b + c)(a - b - c)$

Answer 2

Answer:

$Faxtorisation \:of\\ a^{2}-2ab+b^{2}-c^{2}\\=(a-b+c)(a-b-c)$

Step-by-step explanation:

$Given \: expression \\a^{2}-2ab+b^{2}-c^{2}\\=(a^{2}-2ab+b^{2})-c^{2}\\</p><p>= (a-b)^{2}-c^{2}$

/* By algebraic identity:

$\boxed { x^{2}-2xy+y^{2}=(x-y)^{2}}$

*/

=$[(a-b)+c][(a-b)-c]$

/* By algebraic identity:

$\boxed {x^{2}-y^{2}=(x+y)(x-y)}$

*/

=$(a-b+c)(a-b-c)$

Therefore,

$Faxtorisation\: of\\ a^{2}-2ab+b^{2}-c^{2}\\=(a-b+c)(a-b-c)$

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