Question

(a2-4) (9-b2) + 24ab

Answer 1

Hello mate

Here is ur answer


Trying to factor as a Difference of Squares :

 1.1      Factoring:  a2-4 

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 - AB + AB - B2 = 
         A2 - B2

Note :  AB = BA is the commutative property of multiplication. 

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 4 is the square of 2
Check :  a2  is the square of  a1 

Factorization is :       (a + 2)  •  (a - 2) 

Trying to factor as a Difference of Squares :

 1.2      Factoring:  9 - b2 

Check :  9  is the square of  3 
Check :  b2  is the square of  b1 

Factorization is :       (3 + b)  •  (3 - b) 

Equation at the end of step  1  :

(a+2)•(a-2)•(b+3)•(3-b)+24ab

Step  2  :

Final result :

-a2b2 + 9a2 + 24ab + 4b2 - 36


Hope it helps u

Answer 2

hello friend ❤️❤️☺️☺️


(a²-4) (9-b²)+24ab


=> a²(9-b²)+4(9-b²)+24ab

=> 9a²-a²b²+36-4b²+24ab

=> -a²b²+9a²-4b²+24ab+36

hope it's help