Question

a²– 6ab + 12bc - 4c²


factorisation,please help. ​

Answer 1

Answer:

Hello friend

Step-by-step explanation:

Given, a2 – 6ab + 12bc – 4c2

⇒ a2 – 4c2 – 6ab + 12bc

⇒ (a2 – (2c)2) – 6b(a – 2c)

[Since, from the identity III we know that, (x2 – y2) = (x – y)(x + y)]

⇒ (a + 2c)(a – 2c) – 6b(a – 2c)

⇒ (a – 2c)(a + 2c – 6b)

Answer 2

Step-by-step explanation:

in the problem there is a error

where the constant term