Question

a2-8a+16 factorize plz​

Answer 1

Answer:

The answer is $(a-4)^2$

Step-by-step explanation:

Given expression

  $a^2-8a+16$

$=a^2-2(a)(4)+(4)^2\\=(a-4)^2$

Using $(x-y)^2=x^2-2xy+y^2$

Answer 2

Answer:

The equation can be factorized as $(x-4)(x-4)$

Step-by-step explanation:

Given the quadratic equation is,

$a^2-8a+16$

To factorize the equation we need to find two numbers whose product is 16 and the sum is -8. Two such numbers are -4 and -4. Hence we can factorize the equation as,

$(x-4)(x-4)$

The root of the equation is 4 and it is a repeated root.