Question

find the area of a Trapezium when the parallel sides are 11 cm and 18 cm and the perpendicular distance between them is 10cm​

Answer 1

Answer:

area of the trapezium

=(11+18)×10/2 sq cm

=29×5 sq cm

=145 sq cm

Answer 2

To find : area of a Trapezium  .

Given : parallel sides are $11$ cm and $18$ cm  and  perpendicular distance between them is  $10$ cm​ .

Solution :

• As per given data we know that parallel sides are $11$ cm and $18$ cm  and  perpendicular distance between them is  $10$ cm​ .
• Area of trapezium = $\frac{1}{2} \times ( sum\ of \ parallel\ sides )\times ( distance \ between \ them )$
• Substituting values in the above formula .

• Area of trapezium $=\frac{1}{2} \times( 11 + 18 ) \times 10$

                                      $\\= \frac{1}{2} \times 29 \times 10 \\= 29\times 5 \\= 145\ cm ^{2}$

Hence , area of trapezium is $145\ cm^{2}$ .