Question

a2+b2=10^2-48 find a and b

Answer 1

The answer will be in a+b manner

a²+b²=10²-48
a²+b²=100-48
a²+b²=52
a+b=√52
a+b=7.211

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Answer 2

Answer:

a=4 and b=6.

Step-by-step explanation:

Given : Expression  $a^2+b^2=10^2-48$

To find : The value of a and b?

Solution :

First we solve the expression,

$a^2+b^2=10^2-48$    

$a^2+b^2=100-48$    

$a^2+b^2=52$

Now, we have to write 52 in such a way that it form of sum of square terms.

Square terms are

1,4,9,16,25,36,49 are all less than 52.

$52=16+36$

$52=4^2+6^2$

Substitute,

$a^2+b^2=4^2+6^2$

On comparing the value of a is 4 and b is 6.

Therefore, a=4 and b=6.