Question

a2+b2= 19, ab=10, a2-b2=?

Answer 1

Answer:

Given:-

a²+b² = 19

ab = 10

we know , that

(a²-b²) = (a+b)(a-b) -------------(1)

now,

(a+b)² = a²+b²+2ab

(a+b)² = 19+2*10 = 39

(a+b) = √39 -------------------(2)

also ,

(a-b)² = a²+b²-2ab

(a-b)² = 19-2*10 = (-1)

(a-b) = √(-1) ---------------(3)

putting value of eqn (2) and (3) in eqn (1) we get,

(a²-b)² = (√39)(√-1) = √(-39) (Ans)

(Mark as brainlist)