Question

(a2-b2)2-a2b2 factorization process please

Answer 1

Answer:

Hey mate,

Here is ur answer......

(a²-b²)²-(ab)²

= [(a²-b²)-ab] [(a²-b²)+ab]

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Answer 2

Answer:

a^2-b^2= (a+b)(a-b)(a+b)(a-b) axaxbxb

=(a+b)^2(a-b)^2a^2b^2

Step-by-step explanation:

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