If ¹¹P↓(r) = ¹²P↓(r-1),find r.
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Answer:
Given:
The equation is,
¹¹pr=¹²p(r-1)
As we know that,
ⁿpr=n!/(n-r)!
¹¹pr=11!/(11-r)!
¹²p(r-1)=12!/(13-r)!
11!/(11-r)!=12!/(13-r)!
(13-r)!/(11-r)!=12!/11!
(13-r)(12-r)(11-r)!/(11-r)!=12×11!/11!
(13-r)(12-r)=12
156-13r-12r+r²=12
r²-25r+144=0
r²-16r-9r+144=0
r(r-16)-9(r-16)=0
(r-9)(r-16)=0
r=9
But not 16, Because 9 is satisfying the above equation....
Step-by-step explanation:
Hope it helps you........
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