a2 +b2 = 23ab; show that: (a+b)/5 = 1/2
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a^2 + b^2 = (a + b)^2 - 2ab
(a + b)^2 - 2ab = 23ab
(a + b)^2 = 25ab
a + b = root of 25ab
a + b = 5 root ab
(a + b) ÷ 5 = root ab
Hence proved.
The question is incorrect.
(a + b)/5 = root ab is the correct option.
Correct the question and ask me.
(a + b)^2 - 2ab = 23ab
(a + b)^2 = 25ab
a + b = root of 25ab
a + b = 5 root ab
(a + b) ÷ 5 = root ab
Hence proved.
The question is incorrect.
(a + b)/5 = root ab is the correct option.
Correct the question and ask me.
Ahaskar1:
thnx
By mistake I wrote incomplete question
okay
please mark my answer as the brainliest.
Answered by
6
Answer:
This question is incorrect. The question will be
a2 + b2 = 23ab show that log (a + b)÷5 = 1/2(log a + log b)
Solution:- a2+b2=23ab
Adding 2ab on both side
a2 + b2 +2ab = 23ab + 2ab
(a+b)2= 25ab
(a+b)2/25= ab
(a+b÷5)2=ab
Taking log both side
Log (a+b÷5)2 = log ab
2log (a+b÷5)= log a + log b
Log (a+b÷5) = 1/2 log a + log b
Step-by-step explanation:
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