Question

a2+b2=25 and ab=12, find a+b and a-b​

Answer 1

Answer:

a^2+b^2= (a+b)^2-2ab

=> 25 = (a+b)^2-2×12

=>(a+b)^2= 49

=> a+b= 7

Again,

a^2+b^2= (a-b)^2+2ab

=> 25= (a-b)^2+2×12

=>(a-b)^2= 1

=>a-b= 1

Answer 2

Step-by-step explanation:

Answer

(a+b)² = a² + 2ab + b²

(a+b)² = (a² + b²) + 2(ab)

(a+b)² = 25 + 2(12)

(a+b)² = 25 + 24

(a+b)² = 49

(a+b)² = 7²

a+b = 7

Using Identity: (a+b)²

(a-b)² = a² - 2ab + b²

(a-b)² = (a² + b²) - 2(ab)

(a-b)² = 25 - 2(12)

(a-b)² = 25 - 24

(a-b)² = 1

(a-b)² = 1²

a-b = 1

Using Identity: (a-b)²

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