a2 + b2 + 2c2 = ab + 2bc+ 2ca. Prove that a = b =c
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Answered by
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I think your answer needs some corrctions.
If 2a² + 2b² + 2c² = 2ab + 2bc + 2ca, prove that a = b = c
Answer is given below :
Now,
2a² + 2b² + 2c² = 2ab + 2bc + 2ca
⇒ a² - 2ab + b² + b² - 2bc + c² + c² - 2ca + a² = 0
⇒ (a - b)² + (b - c)² + (c - a)² = 0
We know that, if the sum of square terms be zero, then each term equals to zero.
So, a - b = 0 ⇒ a = b
b - c = 0 ⇒ b = c
c - a = 0 ⇒ c = a
Thus, combining, we get a = b = c. [Proved]
I hope that it helps you.
If 2a² + 2b² + 2c² = 2ab + 2bc + 2ca, prove that a = b = c
Answer is given below :
Now,
2a² + 2b² + 2c² = 2ab + 2bc + 2ca
⇒ a² - 2ab + b² + b² - 2bc + c² + c² - 2ca + a² = 0
⇒ (a - b)² + (b - c)² + (c - a)² = 0
We know that, if the sum of square terms be zero, then each term equals to zero.
So, a - b = 0 ⇒ a = b
b - c = 0 ⇒ b = c
c - a = 0 ⇒ c = a
Thus, combining, we get a = b = c. [Proved]
I hope that it helps you.
Answered by
0
here is your answer
hope it helps
hope it helps
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