Math, asked by purvanaik21, 4 days ago

(a²+b² - 3a² b+ 7ab²) - (4a³-3a²b + ab²- b²)​

Answers

Answered by ramkuanil
0

Answer:

a) 3a² + 4ab - b² + 7b²- 4ab + 2a² + a² + b²

= 3a² + 2a² + a² - b² + 7b² + b² + 4ab - 4ab

= 6a² + 7b²

b) 5xy - 7x² - 3y² + 4x²y + 5x²y - xy + x² + y²

= -7x² + x² + 4x²y + 5x²y - 3y² + y² + 5xy - xy

= -6x² + 9x²y - 2y² + 4xy

c) 5a² - 2b³ + 3a³b + 7ab² + 3a²b - 5ab² + a³ + b³

- a²b

= a³ + 3a³b - 2b³ + b³ + 5a² + 3a²b - a²b + 7ab²

- 5ab²

= a³ + 3a³b - b³ + 5a² + 2a²b + 2ab²

Step-by-step explanation:

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