Question

a²+b²-4ac+4c². I need the answer of this question guys. ​

Answer 1

Answer:

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Answer 2

Answer:

\begin{lgathered}= a ^{2} + (2c)^{2} - 2(a)(2c) - b ^{2} \\ using \: identity \: (a - b) ^{2} = a^{2} + b ^{2} - 2ab \\ (a - 2c) ^{2} - b^{2} \\ using \: identity \: a ^{2} - b^{2} = (a + b)(a - b) \\ (a - 2c - b)(a - 2c + b)\end{lgathered}

=a

2

+(2c)

2

−2(a)(2c)−b

2

usingidentity(a−b)

2

=a

2

+b

2

−2ab

(a−2c)

2

−b

2

usingidentitya

2

−b

2

=(a+b)(a−b)

(a−2c−b)(a−2c+b)

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