a²+b²÷a²-b²=25÷7 find a/b
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a/b=4/3.
Step-by-step explanation:
If a²−b²=7 and a²+b²=25, then what is the value of a/b?
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Answered:-
2 years ago
Let a^2-b^2=7 be equation (1)
& a^2+b^2=25 be equation (2)
From equation (1)
a^2=7+b^2
Substitute above equation in equation (2), we get,
7+b^2+b^2=25
7+(2*b^2)=25
(2*b^2)=25–7
(2*b^2)=18
b^2=18/2
b^2=9
Substitute the value of b^2 in equation (1),
We get,
a^2–9=7
a^2=7+9
a^2=16
Thus, a^2/b^2=16/9
a/b=√(16/9)
a/b=4/3.
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