(a²+b²) (-a²+b²) solve the algebraic expression
Answers
Answered by
0
Answer:
a²+b²
Step-by-step explanation:
(a²+b²)(-a²+b²)
talking (-) common
-[(a²+b²)(a²-b²)]
-[a²-b²]
a²+b²
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Answered by
0
Answer:
The answer is 4a^2b^2
Step-by-step explanation:
a^2+b^2 whole square = a+bwhole^2-2ab
And,
-a^2+b^2 whole square = -a+b whole^2-2ab
Then the following equation formed
= a+b whole^2-2ab X -a+b whole^2-2ab
= a+b-a+b whole^2+4a^2b^2
after cutting the terms
= 0^2+4a^2b^2
=4a^2b^2
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