a2+b2+c2-ab-bc-ca equal to what
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Step-by-step explanation:
a²+b²+c²-ab-bc-ca
=1/2(2a²+2b²+2c²-2ab-2bc-2ca)
=1/2[a²-2ab+b²+b²-2bc+c²+c²-2ca+a²]
=1/2[(a-b)²+(b-c)²+(c-a)²]
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