Question

a2+b2+c2=ab+bc+ca what is the value of a,b,c

Answer 1

Step-by-step explanation:

A^2+b^2+c^2-ab-bc-ac

=1/2(2a^2+2b^2+2c^2-2ab-2bc-2ac)

=1 /2{(a-b)^2+(b-c)^2+(c-a)^2}

if a,b,c are real numbers then,(a-b)^2,(b-c)^2and(c-a)^2 are positive square of every real number is positive. So,

a^2+b^2+c^2-ab-bc-ca is always positive