Question

a2+b2=
$2 {58}^{2}$
​

Answer 1

homologous series is a sequence of compounds with the same functional group and similar chemical properties in which the members of the series can be branched or unbranched, or differ by -CH2.

Answer 2

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Formula used :-

$\large\bold\red{ {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy }$

Solution:-

${258}^{2} = {(250 + 8)}^{2} \\ = {250}^{2} + {8}^{2} + 2 \times 250 \times 8 \\ = 62500 + 64 + 4000 \\ = 66564$

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