Question

a2-b2, where a=5+2 root 6,b=5+2 root6

Answer 1

applying the property of a2-b2 = (a+b)(a-b);

Now putting the value of a and b in above formula;

we get;

a2-b2 =

$(5 + 2 \sqrt{6} + 5 + 2 \sqrt{6} )(5 + 2 \sqrt{6} - 5 - 2 \sqrt{6} )$

$= (1 0 + 4 \sqrt{6} )(0)$

Any term which is multiply by zero result will get zero;

= 0