-(a²+b²)x = (a²-b²)a - 2a²b
find the value of x
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Solution :
-(a²+b²)x = (a²-b²)a - 2a²b
=> x = [(a²-b²)a - 2a²b]/[-(a²+b²)]
= [2a²b-(a²-b²)a]/(a²+b²)
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madhav2684:
uhh i need the answer
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