Question

(a²b/3 -ab²/4) (a-b)​

Answer 1

Answer:

Hope it helps

Step-by-step explanation:

$= (\frac{a^2b}{3}-\frac{ab^2}{4})(a-b)\\\\\\= (\frac{4a^2b}{12}-\frac{3ab^2}{12})(a-b)\\\\\\=(\frac{4a^2b-3ab^2}{12})(a-b)\\\\\\=[a(\frac{4a^2b-3ab^2}{12})-b(\frac{4a^2b-3ab^2}{12})]\\\\\\=(\frac{4a^3b-3a^2b^2}{12})-(\frac{4a^2b^2-3ab^3}{12})\\\\\\=\frac{4a^3b-3a^2b^2-4a^2b^2+3ab^3}{12}\\\\\\= \frac{4a^3b-7a^2b^2+3ab^3}{12}\\\\\\=\frac{(ab)(4a^2-7ab+3b^2)}{12}\\\\\\=\frac{(ab)[(4a^2-3ab-4ab+3b^2)]}{12}\\\\\\=\frac{(ab)[(a(4a-3b)-b(4a-3b)]}{12}\\\\\\=\frac{(ab)(a-b)(4a-3b)}{12}$