A²b²+b²c²+c²a²=(ab+bc+ca)²-2[(ab)(bc)+(bc)(ca)+(ab)(ca)]-->
(ab+bc+ca)²-2abc(b+c+a).
Preciso da demonstração passo a passo...
Answers
Answered by
1
Answer:
Correct option is
D
p
2
−2q
We know that
(a+b+c)
2
=a
2
+b
2
+c
2
+2(ab+bc+ca)
Given ab+bc+ca=q
a+b+c=p
=>p
2
=a
2
+b
2
+c
2
+2(q)
=>a
2
+b
2
+c
2
=p
2
−2q
Similar questions