Question

a²b²x²-(a²-b²)x + 1=0 ,solve​

Answer 1

Step-by-step explanation:

2a^42b^4-2a^4-2b^4*x+1=0

0*0*x+1=o

0*0*1+x=0

0+x=0

x=0

Answer 2

Step-by-step explanation:

a²b²x²-(a²-b²)x+1= 0

x= [(a²-b²)±√(a²-b²)²-4a²b²] / 2a²b²

x = [ (a²-b²)±√(a⁴+b⁴-6a²b²] / 2a²b²

hope this helps you