Question

a2x = b, b2y = C, c2z = a, then find the value of xyz.​

Answer 1

Answer:

a²x = b

x = b/a²

b²y = c

y = c/b²

c²z = a

z = a/c²

x*y*z:

= (b/a²)*(c/b²)*(a/c²)

= 1/(abc)

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Answer 2

Answer:

so just add all

Step-by-step explanation:

by adding 2+2+2 =6 so 6÷2 which is 3 so the value of x,y,z is 3

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