Question

a³-1/27a³ please do it it's urgent ​

Answer 1

Answer:

Step-by-step explanation:

a³-1/27a³

a³-(1/3a)³

a³-b³=(a – b) (a² + ab + b² )

=(a-1/3a)(a²+a*(1/3)(a)+(1/3a)²)

=(a-1/3a)(a²+1/3+1/9a²)

Answer 2

Answer:

a^3-1/27^3

(a)^3-(1/3)^3

using identity a^3-b^3=(a-b)(a^2+b^2+ab)

(a-1/3)(a^3+1/27+a/3)

a^4+a/27+a^2/3-a^3/3-1/81-a/9

(81a^4+3a+27a^2-27a^3-19a)/81

(81a^4-27a^3+27a^2-6a-1)/81

(81a^4-27a^3+27a^2-6a)/81=1

3a(27a^3-9a^2-9a-2)=81