Question

a3-2a2+3a-18 is exactly decided by a-3or not​

Answer 1

Answer:

$p(a) = {a}^{3} - {2a}^{2} + 3a - 18 \\ g(a) = a - 3 \\ g(a) = 0 \\ a - 3 = 0 \\ a = 3$

$putting \: p(a) = 3 \\ p(3) = {3}^{3} - 2 \times {3}^{2} + 3 \times 3 - 18 \\ = 27 - 2 \times 9 + 9 - 18 \\ = 18 - 18 \\ = 0$

since remainder is 0 g(a) is factor of p(a)

Answer 2

Answer:

0 because 5 -4 =1 and 1-1¥0