a³+2a²-a+5 where a=-4plzz solve it
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Answer:
given a=-4
putting the value of a in given equation
that is a^3+2a^2-a+5
(-4)^3+2(-4)^2-(-4)+5
-64+2×16+4+5
-64+41=-23
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Question:-
a³+2a²-a+5 where a=-4
Answer:-
- a³+2a²-a+5
- (-4)³+2(-4)²-(-4)+5
- -64+2(-4)²-(-4)+5
- -64+2x16-(-4)+5
- -64+32-(-4)+5
- -32-(-4)+5
- -32+4+5
- -28+5
- -23
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