Question

a3/8 + b3/27 factorise using identity​

Answer 1

a^3/6 + b^3/27

= (a/2)^3 + (b/3)^3

As we know that ,

x^^3 + y^3 = (x + y) X (x^2 - xy + y^2)

So in the same way,

(a/2)^3 + (b/2)^3

= {(a/2)^2 - [(a/2) X (b/3)] + (b/3)^2} X {(a/2) + (b/3)}

= {a^2/4 - ab/6 + b^2/9} X {a/2 + b/3}