Math, asked by amitjimmy230336, 5 months ago

p+p²+p³+p⁴+p⁵+p⁶+p⁷/p^-3+p^-4+p^-5+p^-6+p^-7+p^-8+p^-9​

Answers

Answered by shaiksubhanuddin123
0

Answer:

\underline{\textsf{Given:}}

Given:

\mathsf{\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}}

p

−3

+p

−4

+p

−5

+p

−6

+p

−7

+p

−8

+p

−9

p+p

2

+p

3

+p

4

+p

5

+p

6

+p

7

\underline{\textsf{To find:}}

To find:

\textsf{The value of}The value of

\mathsf{\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}}

p

−3

+p

−4

+p

−5

+p

−6

+p

−7

+p

−8

+p

−9

p+p

2

+p

3

+p

4

+p

5

+p

6

+p

7

\underline{\textsf{Solution:}}

Solution:

\textsf{Consider,}Consider,

\mathsf{\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}}

p

−3

+p

−4

+p

−5

+p

−6

+p

−7

+p

−8

+p

−9

p+p

2

+p

3

+p

4

+p

5

+p

6

+p

7

\textsf{Multiply both numerator and denominator by}\,\mathsf{p^{10}}Multiply both numerator and denominator byp

10

\mathsf{=\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}{\times}\dfrac{p^{10}}{p^{10}}}=

p

−3

+p

−4

+p

−5

+p

−6

+p

−7

+p

−8

+p

−9

p+p

2

+p

3

+p

4

+p

5

+p

6

+p

7

×

p

10

p

10

\mathsf{=\dfrac{(p+p^2+p^3+p^4+p^5+p^6+p^7)p^{10}}{p^7+p^6+p^5+p^4+p^3+p^2+p}}=

p

7

+p

6

+p

5

+p

4

+p

3

+p

2

+p

(p+p

2

+p

3

+p

4

+p

5

+p

6

+p

7

)p

10

\mathsf{=\dfrac{(p+p^2+p^3+p^4+p^5+p^6+p^7)p^{10}}{p+p^2+p^3+p^4+p^5+p^6+p^7}}=

p+p

2

+p

3

+p

4

+p

5

+p

6

+p

7

(p+p

2

+p

3

+p

4

+p

5

+p

6

+p

7

)p

10

\mathsf{=p^{10}}=p

10

\underline{\textsf{Answer:}}

Answer:

\mathsf{\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}=p^{10}}

p

−3

+p

−4

+p

−5

+p

−6

+p

−7

+p

−8

+p

−9

p+p

2

+p

3

+p

4

+p

5

+p

6

+p

7

=p

10

Answered by sameera63
0

Answer

p28/-33-9

Step-by-step explanation:

p28/-3p-4p-5p-6p-7p-8p-9

p28/-33p-9

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