a³+b³-8c³+6abc factorise using suitable identity
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Answer:
Step-by-step explanation:
remember this,
a³+b³+c³+3abc = (a +b+c)(a²+b²+c² -ab-bc-ca)
from the given expression , a = a, b= b , c= -2c
now put the values to get the factorized form
hope u get it n let me know......................................
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