Math, asked by shreyashivanna65, 11 months ago

a³+b³-8c³+6abc factorise using suitable identity​

Answers

Answered by nidhiakara
5

Answer:

Step-by-step explanation:

     remember this,

a³+b³+c³+3abc = (a +b+c)(a²+b²+c² -ab-bc-ca)

    from the given expression , a = a, b= b , c= -2c

         now put the values to get the factorized form

          hope u get it n let me know......................................

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