Question

(a3-b3)÷(a-b) divude

Answer 1

(a3 - b3) ÷ (a-b)

By Identity,
(a3 - b3) = (a-b)(a2 + b2 + ab)

Hence,
(a3 - b3) ÷ (a-b)
(a-b)(a2 + b2 + ab) ÷ (a-b)
=a2 + b2 + ab

Answer 2

Correct question is "Find value of (a³-b³)÷(a-b)"

Answer:

Required value is ${a}^{2} + ab + {b}^{2}$

Step-by-step explanation:

Given,(a³-b³)÷(a-b)

We want to find the value of this.

This is a division of Algebra.

Now,(a³-b³)÷(a-b)

$= \frac{ {a}^{3} - {b}^{3} }{a - b} \\ = \frac{(a - b)( {a}^{2} + ab + {b}^{2} ) }{a - b} \\ = {a}^{2} + ab + {b}^{2}$

Here applied formula,

${a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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