Math, asked by mittals3814, 11 months ago

A³+b³+c³-3abc÷ a²+b²+c²-ab-bc-ca

Answers

Answered by adrija19

1

Answer:

(a^3+b^3+c^3-3abc)÷(a^2+b^2+c^2-ab-bc-ca)

= a+b+c

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