Math, asked by pratapnayak57, 18 days ago

a³+b³+c³-3abc/ab+bc+ca-a²+b²-c²
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Answers

Answered by TheHappiness

4

Answer:

a³ + b³ + c³ -3abc = ( a + b + c)(a² + b² + c² - ab - bc - ca) .

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