A3-digit number 4A3 is added to another 3-digit number 984 to give four digit number 13B7,which is divisible by 11.find (a+b).
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so here you can simply take the lower digit of 4A3 assume a=0 403 and adding it to 984 so total is 1387 so here you can find that total is greater 1387 but less than 1398 so b/w those 2 no. only digit divisibke by 11 which ends with 7 is 1397 so here 1397-1387=10 so here a must be 1 and b is 9 so a+b = 9+1=10
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