Question

a4 – 2a3b + 3ab3 + 4a2b2 + 3b4, – 2a4 – 5ab3 + 7a3b – 6a2b2 + b4
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Answer 1

Answer:

Given expressions are : a4−2a3b+3ab3+4a2b2+3b4   and  −2a4−5ab3+7a3b−6a2b2+b4

Required sum =(a4−2a3b+3ab3+4a2b2+3b4)+(−2a4−5ab3+7a3b−6a2b2+b4)

=a4−2a3b+3ab3+4a2b2+3b4−2a4−5ab3+7a3b−6a2b2+b4

Rearranging and collecting like terms,

=a4−2a4−2a3b+7a3b+3ab3−5ab3+4a2b2−6a2b2+3b4+b4

=(1−2)a4+(−2+7)a3b+(3−5)ab3+(4−6)a2b2+(3+1)b4

= −a4+52a3b−2ab3−2a2b2+4b4