Question

a4+b4-7a2b2
factorise​

Answer 1

Answer:

a

4

+b

4

−7a

2

b

2

Above terms can be written as

a

4

+b

4

+2a

2

b62−9a

2

b

2

we know that (a+b)

2

=a

2

+2ab+b

2

[(a

2

)

2

+(b

2

)

2

+(2×a

2

×b

2

)]−(3ab)

2

(a

2

+b

2

)

2

−(3ab)

2

we know that (a+b)

2

=a

2

+2ab+b

2

[(a

2

)

2

+(b

2

)

2

+(2×a

2

×b

2

)]−(3ab)

2

(a

2

+b

2

)

2

−(3ab)

2

We know that a

2

−b

2

=(a+b)(a−b)

(a

2

+b

2

+3ab)(a

2

+b

2

−3ab)

Answer 2

Step-by-step explanation:

$= {a}^{4} + {b}^{4} - 7 {a}^{2} {b}^{2} \\ = {( {a}^{2}) }^{2} + { ({b}^{2} )}^{2} - 2 {a}^{2} {b}^{2} - 5 {a}^{2} {b}^{2} \\ = {( {a}^{2} - {b}^{2} )}^{2} - 5 {a}^{2} {b}^{2} \\ = {((a + b)(a - b))}^{2} - 5 {a}^{2} {b}^{2} \\ = {(a + b)}^{2} {(a - b)}^{2} - 5 {a}^{2} {b}^{2}$

HOPE THIS HELPS YOU

MARK ME BRAINLIEST