Question

a⁴-b⁴
factorise the equation fast​

Answer 1

Answer:

$(a - b)(a + b)( {a}^{2} + {b}^{2} )$

Step-by-step explanation:

Using the identity,

${x}^{2} - {y}^{2} = (x + y)(x - y)$

We have,

${a}^{4} - {b}^{4} \\ = ( {a}^{2} - {b}^{2} )( {a}^{2} + {b}^{2} ) \\ = (a - b)(a + b)( {a}^{2} + {b}^{2} )$

Answer 2

Answer:(a^2+b^2) (a+b) (a-b)

Step-by-step explanation:

a^4-b^4= (a^2) ^2- (b^2) ^2

Using, a^2-b^2=(a+b) (a-b) , we get

a^4-b^4= [ a^2+b^2][a^2-b^2],

Again applying, a^2-b^2=(a+b) (a-b), we get

a^4-b^4= (a^2+b^2) (a+b) (a-b)