Question

A40 watt bulb is connected to a source of 220 v. Find the current flowing in it-
(a) 0.18 amperes (b) 1.8 amperes (c)2 amperes (d) 5.5 amperes​

Answer 1

Answer:

A

Explanation:

P= VI

Then I= P/V

I= 40/220

I= 0.18

Answer 2

Answer:

a. 0.18 Amperes

Explanation:

The resistance of bulb:

R=V^2/P

R=220×220/40

R=1210 Ohms

I=V/R

I=220/1210

I=0.18 Amperes