A5. Find the number of tiles of dimensions 1 mx 0.8 m
required to cover a floor of dimensions 80 m x 120 m.
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Answer:
12000 tiles
Step-by-step explanation:
no. of tiles = area of floor/area of one tile
= 120 ×80/1×0.8
= 9600/ 0.8
= 12000
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