Question

A5m 60cm high vertical pole casts a shadow 3m20cm long:Find.The length of the shadow cast by another pole 5m long
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Answer 1

If two quantities increase or decrease together in such a manner that the ratio of their corresponding values remain constant, we say  that the two quantities vary  directly.

In other words x and y are said to vary directly if X/y = k , where k is a positive constant.

In direct Proportion

x/y= k

x=ky

So we can find value of k from known values, and then use the formula to calculate the unknown values.

When two quantities x and y are in direct proportion (or vary directly) they are also written as x∝y.

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Solution:

[Table is in the attachment]

Here height of the pole and length of the

shadow are in direct proportion.

 1m=100cm

5m 60 cm =560cm

3m 20 cm=320cm

10m 50cm=1050cm

 

(i). Let the length of the shadow of

another pole be x.

560/320=1050/x

x×560=1050 × 320

X=(1050×320)/560

X=600 cm

X=6m

Hence,the Length of the shadow of another

pole is 6m.

 

(ii) Let the height of the pole be ‘x’.

560/320=x/500 

X×320=500×560 

X=560×500/320

X=875 cm

X= 8m 75 cm

Hence,  the height of the pole is 8m 75cm.

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Hope this will help you...