Physics, asked by 291441, 4 months ago

A6 kg bowling ball rolls towards a 0.7 kg bowling pin at a velocity of 2.8 m/s and strikes the pin. If the pin is moving
3.4 m/s after the collision, what is the velocity of the bowling ball after the collision? ​

Answers

Answered by RISH4BH
14

GiveN :-

  • A 6 kg bowling ball rolls towards a 0.7 kg bowling pin at a velocity of 2.8 m/s and strikes the pin. If the pin is moving 3.4 m/s after the collision .

To FinD :-

  • The velocity of the bowling ball after the collision .

SolutioN :-

Given that , a 6 kg bowling ball rolls towards a 0.7 kg bowling pin at a velocity of 2.8 m/s and strikes the pin. If the pin is moving 3.4 m/s after the collision . We need to find velocity of the bowling ball after the collision .Here we can use the Law of Conservation of Momentum according to which in a system the Total momentum remains conserved .

★Using the Law of Conservation of Momentum:-

\sf\dashrightarrow \pink{m_1u_1+m_2u_2=m_1v_1+m_2v_2} \\\\\sf\dashrightarrow (6kg)(2.8 m/s)+(0.7 kg)(0m/s)=(0.7kg)(3.4 m/s)+(6 kg)(v_{(ball)}) \\\\\sf\dashrightarrow  16.8 kg-m/s + 0 = 2.38 m/s + 6v \\\\\sf\dashrightarrow 6v = (16.8-2.38) m/s \\\\\sf\dashrightarrow  6v = 14.42 m/s \\\\\sf\dashrightarrow  \underset{\blue{\sf Required\ velocity}}{\underbrace{\boxed{\pink{\frak{ Velocity_{(ball)}= 2.403 \ m/s }}}}}

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