A70-kg man pushes a 50-kg man by a force of 50N. By what force has the 50-kg man pushed the other man?
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Same force that is 50 N
aayushi75:
As of every action there is equal and opposite reaction
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The Newton 3rd law could be measure by taking proper approaches and pushed the other man by 50N force, it is wrong.
The 70kg person pushes a 50kg man by a force of 50N and F=50N.
This must hand over by coefficient of static friction and N is formal reaction.
So, the equation is termed as coefficient of static friction.
Now, for balancing fr = F so, 50 = kN = k × 500k = 0.1,
hence coefficient of static Friction = 0.1.
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