â7x + â11y = 0 â3x - â5y = 0 by subsituation
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The answer is given below :
Given equations are
7x + 11y = 0 .....(i)
3x - 5y = 0 .....(ii)
From (i), we get
7x = -11y
⇒ x = -11y/7
Now, substituting the value of x in (ii), we get
3(-11y/7) - 5y = 0
⇒ -33y/7 - 5y = 0
⇒ (-33/7 - 5)y = 0
⇒ y = 0
Putting y = 0 in (i), we get
7x + (11 × 0) = 0
⇒ 7x = 0
⇒ x = 0
Therefore, the required solution of the given equations be
x = 0 and y = 0.
Thank you for your question.
Given equations are
7x + 11y = 0 .....(i)
3x - 5y = 0 .....(ii)
From (i), we get
7x = -11y
⇒ x = -11y/7
Now, substituting the value of x in (ii), we get
3(-11y/7) - 5y = 0
⇒ -33y/7 - 5y = 0
⇒ (-33/7 - 5)y = 0
⇒ y = 0
Putting y = 0 in (i), we get
7x + (11 × 0) = 0
⇒ 7x = 0
⇒ x = 0
Therefore, the required solution of the given equations be
x = 0 and y = 0.
Thank you for your question.
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