y= x(dy/dx)+x/(dy/dx) is what order and degree
TanurRizal:
First order, 1 degree ODE?
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The answer is given below :
DEFINITIONS :
Order : The order of a differential equation is the highest ordered derivative term present in the equation.
Degree : The degree of a differential equation is the power of the highest order derivative term present in the equation. The power must rationalised and be an integer.
SOLUTION :
The given differential equation is
y = x(dy/dx) + x/(dy/dx)
⇒ y(dy/dx) = x(dy/dx)² + x
⇒ x(dy/dx)² - y(dy/dx) + x = 0
The highest ordered derivative term present in the equation is dy/dx, whose order is 1.
So, the order of the differential equation is 1.
The power of the highest ordered derivative term (dy/dx) is 2.
Hence, the degree of the differentiatial equation is 2.
Thank you for the question.
DEFINITIONS :
Order : The order of a differential equation is the highest ordered derivative term present in the equation.
Degree : The degree of a differential equation is the power of the highest order derivative term present in the equation. The power must rationalised and be an integer.
SOLUTION :
The given differential equation is
y = x(dy/dx) + x/(dy/dx)
⇒ y(dy/dx) = x(dy/dx)² + x
⇒ x(dy/dx)² - y(dy/dx) + x = 0
The highest ordered derivative term present in the equation is dy/dx, whose order is 1.
So, the order of the differential equation is 1.
The power of the highest ordered derivative term (dy/dx) is 2.
Hence, the degree of the differentiatial equation is 2.
Thank you for the question.
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