AaBBCc, in this genotype, how many gametes can be formed?
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Gametes for AaBBCc:
ABC, aBC, ABc and aBc. There are four possibilities in this case, because the individual is heterozygous for two of the genes and homozygous for gene B. There is a 25% chance of each gamete.
After making Punnet square we will find that there will be 16 gametes formed.
Hope this helps you.....:)
ABC, aBC, ABc and aBc. There are four possibilities in this case, because the individual is heterozygous for two of the genes and homozygous for gene B. There is a 25% chance of each gamete.
After making Punnet square we will find that there will be 16 gametes formed.
Hope this helps you.....:)
Sneha11111111111:
how can it possible? explain please
how many kind of gametes can produced?
3 kinds
kon kon sa
There can be 9 types of gametes produce
They are AABBCC = 1, AABBCc = 2, AABBcc = 1, AaBBCC = 2, AaBBCc = 4, AaBBcc = 2, aaBBCC = 1, aaBBCc = 2, aaBBcc = 1
And from this the Genotypic ratio will be 1:2:1:2:4:2:1:2:1
Hope now it is understood dear...
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1
Answer:
type of gametes = 4
Explanation:
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