Question

AABC is right angled at A. In each of the following write down the values of sin B,cos C
() AB =20, AC = 21, BC = 29;
and tan B​

Answer 1

Answer:

sin B = 21 / 29

cos C = 21 / 29

tan B = 21 / 20

Step-by-step explanation:

Given, AB = 20 , AC = 21 and BC = 29

Also given that the triangle is right angled at A.

So, BC becomes hypotenuse.

Now,

sin B = AC / BC (since sin x = opposite side to x / hypotenuse)

==> sin B = 21 / 29

cos C = AC / BC ( since cos x = adjacent side to x / hypotenuse )

==> cos C = 21 / 29

tan B = AC / AB ( since tan x = opposite side to x / adjacent side to x )

==> tan B = 21 / 20

I Hope this answer is helpful :)

Answer 2

Answer:

La+Lb+Lc+Ld=360

Step-by-step explanation:

so, 20±21±29±x=360

70+x=360

x=360-70

x=290.

I hope it helps you...