Question

Aakar a car accelerates uniformly from 18 kilometre per hour to 36 km per hour in 5 seconds calculate the acceleration and the distance covered by the car in that time

Answer 1

Answer:

a = 1m/s square

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Answer 2

✬ Acceleration = 1 m/s² ✬

✬ Distance Covered = 37.5 m ✬

Explanation:

Given:

• Uniform velocity (u) of car is 18 km/h.
• Final velocity (v) of car is 36 km/h.
• Time take by car for acceleration is 5 seconds.

To Find:

• What is the acceleration of car and distance covered by it ?

Formula to be used:

• v = u + at
• s = ut + 1/2at²

Solution: First , we need to change the velocity in m/s from km/h. For this multiply by 5/18.

• u = 18 $\times$ 5/18 = 5 m/s.
• v = 36 $\times$ 5/18 = 10 m/s.

Putting the values on formula

$\implies{\rm }$ v = u + at

$\implies{\rm }$ 10 = 5 + a $\times$ 5

$\implies{\rm }$ 10 = 5 + 5a

$\implies{\rm }$ 10 – 5 = 5a

$\implies{\rm }$ 5 = 5a

$\implies{\rm }$ 5/5 = a

$\implies{\rm }$ 1 m/s² = a

Hence , The acceleration of the car is 1 m/s².

Now, For finding distance use the second formula:-

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 5 $\times$ 5 + 1/2 $\times$ 1 $\times$ 5²

$\implies{\rm }$ s = 25 + 25/2

$\implies{\rm }$ s = 25 + 12.5

$\implies{\rm }$ s = 37.5 m

Hence, the distance covered by car in that time is 37.5 m.