Question

Aakriti decided to distribute milk in an orphanage on her birthday. The supplier brought two milk containers which contain 398 l and 436 l of milk. The milk is to be transferred to another containers so 7 l and 11 l of milk is left in both the containers respectively (a) What will be the maximum capacity of the drum? (b) What qualities/values were shown by Aakriti?

Answer 1

a)To find The maximum  capacity  of the drum we subtract the milk left (7l & 11l)in the containers from 398 l and 436 l and then calculate the HCF of the new numbers.

New numbers are : 398 -7= 391 l and 436 -11= 425 l
We have to find the HCF of 391 l & 425 l

On applying euclid's division Lemma for 391 and 425.

425 = 391 × 1 + 34
391 = 34×11 + 17
34 = 17 × 2 + 0

Remainder is 0 and the last divisor is 17.
So, HCF of 391 l & 425 l is 17.
Hence, the maximum  capacity  of the drum is 17 l.

b)Charity, concern for others etc.

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Answer 2

Answer:

To find The maximum  capacity  of the drum we subtract the milk left (7l & 11l)in the containers from 398 l and 436 l and then calculate the HCF of the new numbers.

New numbers are : 398 -7= 391 l and 436 -11= 425 l

We have to find the HCF of 391 l & 425 l

On applying euclid's division Lemma for 391 and 425.

425 = 391 × 1 + 34

391 = 34×11 + 17

34 = 17 × 2 + 0

Remainder is 0 and the last divisor is 17.

So, HCF of 391 l & 425 l is 17.

Hence, the maximum  capacity  of the drum is 17 l.

b)Charity,for others etc.