Question

Aanswer the question fast (step by step )​

Answer 1

$\underline{\huge\mathfrak{Answer:}}$

$\underline{\textbf{Standard Form:}}$

The form fractions , in which the numbers should be in the simplest form , i.e , the numerator and denominator should have no common factor other than 1 , and the denominator cannot be negative is called the standard form .

According to the question :-

i) $\frac{-3}{ 19}$

Here , let us match the required conditions for being in the standard form :

★ The denominator is positive .

★ The numerator and denominator are coprime .

So , the above given number is in the standard form .

ii) $\frac{ 4}{-7}$

★ The numerator and denominator are coprime .

★ The denominator is negative .

So , the above given fraction is not in its standard form . The standard from would be :

$\frac{-4}{ 7}$

iii) $\frac{14}{35}$

★ The numerator and denominator aren't coprime .

★ The denominator is positive .

So , it is not in the standard form as it is not in its sinplest form . The standard form would be the simplest form of this fraction , i.e :

$\frac{2}{5}$

iv) $\frac{8}{-72}$

★ The numnerator and denominator are not coprime .

★ Denominator is negative .

So , the fraction isn't in the standard form . The standard form of this fraction would be :

$\frac{-1}{ 9}$